Question #9678

if a radioactive material has a half-life of 2 years, a sample is reduced to 1/8 of its mass in?

Expert's answer

if a radioactive material has a half-life of 2 years, a sample is reduced to 1/8 of its mass in?

According to the law of radioactive decay


N=2tT=18t=Tlog218=Tlog28=3T=6yearsN = 2 ^ {- \frac {t}{T}} = \frac {1}{8} \gg t = - \mathrm {T} \log_ {2} \frac {1}{8} = \mathrm {T} \log_ {2} 8 = 3 T = 6 \mathrm {y e a r s}

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