The uncertainty in energy is connected with the lifetime of the corresponding excited state via the following expression:
ΔE⋅Δt=ℏ Hence:
ΔE=Δtℏ=10−86.63⋅10−34J=6.63⋅10−26J As long as
1eV=1.6⋅10−19J,we obtain
ΔE=1.6⋅10−196.63⋅10−26≈4.1⋅10−7eV
Answer: 4.1*10-7 eV.
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