living matter has an activity of 260 bq/kg due to carbon 14. if a sample of wood from burial site has an activity of 155 bq/kg, estimate the age of the site. half-life of carbon 14 is 5730 years
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Expert's answer
2018-04-30T08:02:08-0400
Activity of the sample is decreasing as: A=A_0 2^(-T/T_(1/2) ) T_(1/2)=5730 years-halflife time. A_0=260 bq/kg-initial activity A=155 bq/kg-activity at time T So, A=A_0 2^(-T/T_(1/2) )→T=T_(1/2) log_2〖A_0/A〗=5730*log_2〖260/155〗=4276 years
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