Answer on Question #76235 Physics / Atomic and Nuclear Physics
An object starts from rest and accelerates for a=0.24 meter per second square for t1=2 minutes and continues at a steady speed for t2=3 minutes and slow down to stop for t3=1 minute. A) Draw graph for the motion. B) Calculate the maximum velocity in km/hr. C) Determine the retardation. D) Find the displacement in 5 minutes.
Solution:

A)
B) vmax=at1=0.24×2×60=28.8sm=103.68hkm
C) a3=t30−vmax=600−28.8=−0.48s2m
D) s=2vmaxt1+vmaxt2=228.8×2×60+28.8×3×60=6912m
Answers: 103.68hkm , −0.48s2m , 6912 m
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