Question

A student is carrying out an experiment with a cobalt-60 source of labelled activity 0.3 MBq. She holds the source in tongs 25 cm long for the duration of the experiment which is 6 minutes. Calculate the maximum dose and the maximum dose equivalent that she could receive. (The relevant exposure rate constant is 0.35 µSv/ MBq h at 1m).

Answer 1

Answer on Question #68388, Physics / Atomic and Nuclear Physics

A student is carrying out an experiment with a cobalt-60 source of labelled activity 0.3 MBq. She holds the source in tongs 25 cm long for the duration of the experiment which is 6 minutes. Calculate the maximum dose and the maximum dose equivalent that she could receive. (The relevant exposure rate constant is 0.35 µSv/ MBq h at 1m).

Solution:

The maximum dose:

H = k×λ×A×t (1), where k is the coefficient, λ is the relevant exposure rate constant, A is the activity of source, t is the time

Of (1) ⇒ H = 4×0.35 µSv/MBq ×0.3 MBq×360 s = 151.2 µSv×s

The maximum dose equivalent:

H_T = k×λ×A (2), where k is the coefficient, λ is the relevant exposure rate constant, A is the activity of source

Of (2) ⇒ H_T = 4×0.35 µSv/MBq ×0.3 MBq = 0.42 µSv

Answer:

151.2 µSv×s

0.42 µSv

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