Question

A 1.0g sample of pure KCL from chemistry stock room is found to be radioactive and to decay at the rate of 1600 counts/sec.the decay are traced to be element potassium and in particular to isotope potassium 40 which constitude 1.18% of normal potassium.calculate half of this decay

Answer 1

Answer on Question #64424, Physics / Atomic and Nuclear Physics

A 1.0g sample of pure KCL from chemistry stock room is found to be radioactive and to decay at the rate of 1600 counts/sec. the decay are traced to be element potassium and in particular to isotope potassium 40 which constitute 1.18% of normal potassium. Calculate half of this decay

Find: T₁/₂ - ?

Given:

λ=1600 counts/sec

Solution:

Decay constant λ: λ = ln 2 / T₁/₂ (1)

Of (1) ⇒ T₁/₂ = ln 2 / λ (2)

Of (2) ⇒ T₁/₂ = 0.00043 sec

Answer:

0.00043 sec

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