Question

is it any relation between energy of x rays nd potential between anode nd cathode during x ray production?

Answer 1

Answer on Question #58994, Physics / Atomic and Nuclear Physics

is it any relation between energy of x rays and potential between anode and cathode during x ray production?

Solution:

Consider the braking X-rays. It is formed in the X-ray tube. To the anode and cathode applied the high voltage.

The kinetic energy of the electron is equal of the electric field work:

$$\frac{m v^{2}}{2} = |e| V (1),$$

where $e$ – electron charge ($e = -1,6 \times 10^{-19} \, \text{C}$),

$V$ – potential between anode and cathode

Electrons braked in contact with the surface of the tungsten anode.

The braking of electron generates the formation of X-ray photon.

The energy of the photon: $E = h\theta$ (2),

where $\upsilon$ – frequency of radiation,

$h$ – Planck's constant ($h = 6,626 \times 10^{-34} \, \text{J} \times \text{s}$)

We believe that all the kinetic energy of the electron is converted into energy photon.

Of (1) and (2) $\Rightarrow h\theta_{\max} = |e| V$ (3)

If we assume that the part of electron energy is converted into heat energy, then we can write:

$$h\theta + Q = |e| V (4),$$

where $Q$ – heat energy

Answer:

$$h\theta_{\max} = |e| V$$ $$h\theta + Q = |e| V$$

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