Question #50752

When a metallic surface is illuminated with light of wave length (lambda),the stopping potential is X volt.when the same surface is illuminated of wave length 2lambda, stopping potential is X/3 threshold wave length for the metallic surface is....
1

Expert's answer

2015-02-17T11:32:24-0500

Answer on Question #50752, Physics, Nuclear Physics

When a metallic surface is illuminated with light of wave length (lambda), the stopping potential is XX volt. When the same surface is illuminated of wave length 2lambda, stopping potential is X/3X/3.

Threshold wave length for the metallic surface is...

Answer:

(https://en.wikipedia.org/wiki/Photoelectric_effect)

Will use photoelectric effect equation for this problem:

Energy of illumination photon hcλ\frac{hc}{\lambda} equal to sum of work function φ\varphi and stopping opposite work eXeX.

1. hcλ=φ+eX\frac{hc}{\lambda} = \varphi + eX

2. hc2λ=φ+eX3\frac{hc}{2\lambda} = \varphi + e\frac{X}{3}

This system gives us the result:


hc4λ=φ\frac{hc}{4\lambda} = \varphi


work function φ\varphi may be denoted in mean of trash hold wavelength:


φ=hcλt\varphi = \frac{hc}{\lambda_t}


It is obvious that:


λt=4λ\lambda_t = 4\lambda


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