A 60kg boy and a 40kg girl decide to play "tug of war" on a frictionless surface. In the process, the girl accelerated toward the boy at 3.0m/sec2. what is the acceleration of the boy toward the girl?
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Expert's answer
2011-10-18T12:50:41-0400
F1-force which is& appositional by boy F2-by girl F1-F2=40kg*3m/s^2 Also F1-F2=60kg*a, where a is the acceleration of the boy toward the girl Hence a=40kg*3 m/s^2/60kg =2m/s^2
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