Question

Calculate in J and MeV units the binding energy per nucleus and binding
energy per nucleon for 19 F 9
Mass of proton = 1.00728 u
Mass of neutron = 1.00867 u
Actual atomic mass of 19 F 9 =18.99840u
1 u = 931.9 Mev nucleus-1
=1.493x10-10 J nucleus-1

Answer 1

Answer on Question #44199, Physics, Nuclear Physics

Question:

Calculate in J and MeV units the binding energy per nucleus and binding energy per nucleon for $^{19}_{9}F$

Mass of proton = 1.00728 u

Mass of neutron = 1.00867 u

Actual atomic mass of $^{19}_{9}F$ = 18.99840 u

1 u = 931.9 Mev nucleus-1

= 1.493 × 10⁻¹⁰ J nucleus-1

Answer:

Binding energy is the energy required to split the nucleus of an atom into its component parts. The binding energy per nucleus equals:

$$B = 9 \cdot m_p c^2 + 10 \cdot m_n c^2 - m_F c^2$$

where $m_p$ is mass of the proton, $m_n$ is mass of the neutron, $m_F$ is mass of $^{19}_{9}F$ nucleus.

$$\begin{array}{l} B = (9 \cdot 1.00728 + 10 \cdot 1.00867 - 18.99840) u = 143.345 \text{ MeV} \\ = 2.29653 \cdot 10^{-11} J \end{array}$$

The binding energy per nucleon equals:

$$b = \frac{B}{A}$$

where $A$ is number of nucleons in nucleus.

$$b = 7.54447 \text{ MeV} = 1.2087 \cdot 10^{-12} J$$

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