Question #43892

what is magnitude of total orbital, total spin and total angular momenta for the ground state 4f of vanadium.

Expert's answer

Answer on Question #43892, Physics, Atomic Physics

Task: what is magnitude of total orbital, total spin and total angular momenta for the ground state 4f of vanadium.

Solution:

ground state 4f n=4,l=3,s=12,j=ls=52\Rightarrow n = 4, l = 3, s = \frac{1}{2}, j = l - s = \frac{5}{2}.


Pl=l(l+1)=23;P _ {l} = \hbar \sqrt {l (l + 1)} = 2 \hbar \sqrt {3};Ps=s(s+1)=32;P _ {s} = \hbar \sqrt {s (s + 1)} = \hbar \frac {\sqrt {3}}{2};Pj=j(j+1)=354=235.P _ {j} = \hbar \sqrt {j (j + 1)} = \hbar \sqrt {\frac {3 5}{4}} = \frac {\hbar}{2} \sqrt {3 5}.

Pl=23P_{l} = 2\hbar \sqrt{3} - magnitude of total orbital momenta for the ground state 4f;

Ps=32P_{s} = \hbar \frac{\sqrt{3}}{2} - magnitude of total spin momenta for the ground state 4f;

Pj=235P_{j} = \frac{\hbar}{2}\sqrt{35} - magnitude of total angular momenta for the ground state 4f.

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