Answer on Question #43892, Physics, Atomic Physics
Task: what is magnitude of total orbital, total spin and total angular momenta for the ground state 4f of vanadium.
Solution:
ground state 4f ⇒ n = 4 , l = 3 , s = 1 2 , j = l − s = 5 2 \Rightarrow n = 4, l = 3, s = \frac{1}{2}, j = l - s = \frac{5}{2} ⇒ n = 4 , l = 3 , s = 2 1 , j = l − s = 2 5 .
P l = ℏ l ( l + 1 ) = 2 ℏ 3 ; P _ {l} = \hbar \sqrt {l (l + 1)} = 2 \hbar \sqrt {3}; P l = ℏ l ( l + 1 ) = 2ℏ 3 ; P s = ℏ s ( s + 1 ) = ℏ 3 2 ; P _ {s} = \hbar \sqrt {s (s + 1)} = \hbar \frac {\sqrt {3}}{2}; P s = ℏ s ( s + 1 ) = ℏ 2 3 ; P j = ℏ j ( j + 1 ) = ℏ 35 4 = ℏ 2 35 . P _ {j} = \hbar \sqrt {j (j + 1)} = \hbar \sqrt {\frac {3 5}{4}} = \frac {\hbar}{2} \sqrt {3 5}. P j = ℏ j ( j + 1 ) = ℏ 4 35 = 2 ℏ 35 . P l = 2 ℏ 3 P_{l} = 2\hbar \sqrt{3} P l = 2ℏ 3 - magnitude of total orbital momenta for the ground state 4f;
P s = ℏ 3 2 P_{s} = \hbar \frac{\sqrt{3}}{2} P s = ℏ 2 3 - magnitude of total spin momenta for the ground state 4f;
P j = ℏ 2 35 P_{j} = \frac{\hbar}{2}\sqrt{35} P j = 2 ℏ 35 - magnitude of total angular momenta for the ground state 4f.
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