Question

Calculate the minimum energy of a gama(γ) photon in MeV which can produce one electron-positron pair [rest mass of an electron is 9.1x10^(-31) kg].

Answer 1

Answer on Question #43350, Physics, Atomic Physics

Calculate the minimum energy of a gama(?) photon in MeV which can produce one electron-positron pair [rest mass of an electron is $9.1\cdot 10^{-31}$ kg]. Solution

Minimum energy mass exceed rest mass of pair, that is two mass of electrons ($m_{e}=0.511\,MeV$). Hence

$E_{min}=2m_{e}c^{2}=2\cdot 0.511=1.022\,MeV$

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