Question #38467

calculate the number of alpha particles emitted per second from 1g of radium.assume half life of radium is 1600 years.calculate the volume of helium gas produced by 1g of radium in 1 year

Expert's answer

Answer on Question#38467, Physics, Nuclear Physics

Question:

Calculate the number of alpha particles emitted per second from 1g of radium. Assume half-life of radium is 1600 years. Calculate the volume of helium gas produced by 1g of radium in 1 year.

Answer:

The equation that describes decay is (for Δtt12\Delta t \ll t_{\frac{1}{2}}):


ΔN=λNΔt\Delta N = \lambda N \Delta t


where λ\lambda is the decay constant of radionuclide related to its half-lives t12t_{\frac{1}{2}} by


λ=ln(2)t12\lambda = \frac{\ln(2)}{t_{\frac{1}{2}}}


Number of atoms in 1g of radium equals:


N=NAmMN = N_A \frac{m}{M}


where MM is molar mass, NAN_A is Avogadro constant.

Therefore:


ΔN=ln(2)t12NAmMΔt=3.71010\Delta N = \frac{\ln(2)}{t_{\frac{1}{2}}} N_A \frac{m}{M} \Delta t = 3.7 * 10^{10}


Answer: 3.710103.7 * 10^{10}

For 1 year:


ΔN=ln(2)t12NAmMΔt=3.21015\Delta N = \frac{\ln(2)}{t_{\frac{1}{2}}} N_A \frac{m}{M} \Delta t = 3.2 * 10^{15}


Volume equals:


V=VmΔNNA=22.4lmol3.210156.0210231mol=1.2107lV = V_m \frac{\Delta N}{N_A} = 22.4 \frac{l}{mol} \frac{3.2 * 10^{15}}{6.02 * 10^{23} \frac{1}{mol}} = 1.2 * 10^{-7} l


Answer: 1.2107l1.2 * 10^{-7} l

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