Question #347531

Find the energy of incident photons if a 430-nm violet light is incident on a calcium photoelectrode with a work function of 2.71 eV.

1
Expert's answer
2022-06-02T15:15:11-0400

E=hcλ−A=0.18 eV.E=\frac{hc}{\lambda}-A=0.18~eV.


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