Question

1. What nuclide is formed when 19/10 Ne undergoes beta-plus decay?
2. What nuclide is produced when 234/93 Np undergoes electron capture?

Answer 1

1.

$$\rm{^{19}_{10}} Ne\rightarrow{^{0}_{1}} e+{^{19}_{9}} F$$

2.

$$\rm{^{234}_{93}} Np+{_{-1}^{0}} e\rightarrow{^{234}_{92}} U$$