Question

• What nuclide is formed when 226/88 Ra undergoes alpha decay?

• 64/29 Cu undergoes beta-minus decay. What daughter nuclide is formed?

Answer 1

$_{88}^{226}Ra\to _2^4He+_{86}^{222}Rn,$

$_{29}^{64}Cu\to _{-1}^0e+_{30}^{64}Zn.$