If q1 = 3.0 nC, q2 = -4.0 nC, q3 = 2.0 nC, q4 = -5.0 nC, and q5 to 8 = -1.0
nC, what is the total electrix flux for each of the closed surfaces a, b, c,
and d?
Q=q1+q2+q3+q4+q5=−5 nC,Q=q_1+q_2+q_3+q_4+q_5=-5~nC,Q=q1+q2+q3+q4+q5=−5 nC,
Φ=Qε0=−565 Wb.\Phi=\frac Q{\varepsilon_0}=-565~Wb.Φ=ε0Q=−565 Wb.
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