1. What is the momentum of a proton traveling at π£ = 0.68π?
Rest energy of proton is mc2=938MeVmc^2=938 MeVmc2=938MeV
Speed of proton is v=0.68cv=0.68cv=0.68c
The expression for the relativistic momentum of proton is
p=1(1β(vc)2)mvp=\frac{1}{\sqrt(1-(\frac{v}{c})^2)} mvp=(β1β(cvβ)2)1βmv
=1(1β(0.68cc)2)(938MeV/c2)(0.68c)=\frac{1}{\sqrt(1-(\frac{0.68c}{c})^2)} (938 MeV/c^2)(0.68 c)=(β1β(c0.68cβ)2)1β(938MeV/c2)(0.68c)
=869.9MeV/c=869.9 MeV/c=869.9MeV/c
=870 MeV/c
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