Answer to Question #322770 in Atomic and Nuclear Physics for Jonna

Question

1.   What is the momentum of a proton traveling at 𝑣 = 0.68𝑐?

Answer 1

Rest energy of proton is $mc^2=938 MeV$

Speed of proton is $v=0.68c$

The expression for the relativistic momentum of proton is

$p=\frac{1}{\sqrt(1-(\frac{v}{c})^2)} mv$

$=\frac{1}{\sqrt(1-(\frac{0.68c}{c})^2)} (938 MeV/c^2)(0.68 c)$

$=869.9 MeV/c$

=870 MeV/c