Answer to Question #301018 in Atomic and Nuclear Physics for adiat

Question

The displacement (in meters) of a particle executing simple harmonic motion at any instant of time is

given by, y = 0.2sin2π(350t − 0.30). Calculate i) the amplitude, ii) wave velocity, iii) wave length,

iv) frequency.

Answer 1

1)

$A=0.2~m,$

2)

$v=0.2\cdot 2\pi\cdot 350=440~\frac ms,$

3)

$\lambda=0.2\cdot 350=70~m,$

4)

$\nu={350}\cdot 2\pi=2.2~kHz.$