A metal rod of length 40.0 cm at 20°C is heated through a temperature of 45°C if the new length of the rod
is 40.05 cm calculate its linear expansivity
α=ΔllΔt=5⋅10−5 °C−1.\alpha=\frac{\Delta l}{l\Delta t}=5\cdot 10^{-5}~°C^{-1}.α=lΔtΔl=5⋅10−5 °C−1.
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