Question

A blood corpuscle has a diameter about 9x10-6 in which excited orbit should a hydrogen atom should be so that it is just about as big as the blood corpuscle?

Answer 1

QUESTION:

A blood corpuscle has a diameter about $9 \times 10^{-6}$ in which excited orbit should a hydrogen atom should be so that it is just about as big as the blood corpuscle?

SOLUTION:

The allowed orbit radius of the electron in a hydrogen atom is

$$r_{\mathrm{e}} = \frac{n^{2} \hbar^{2}}{k_{\mathrm{e}} e^{2} m_{\mathrm{e}}}$$

Where $m_{\mathrm{e}}$ is the electron's mass, $e$ is the charge of the electron, $k_{\mathrm{e}}$ is Coulomb's constant, $\hbar = h / 2\pi$, $n$ is orbit number.

So,

$$n = \sqrt{\frac{r_{\mathrm{e}} k_{\mathrm{e}} e^{2} m_{\mathrm{e}}}{\hbar^{2}}}$$

$n = 414.7$

So, electron must be at least at 415 orbit.

ANSWER:

415