What is the force between two protons that are separated by 1.0 mm? The charge of a proton is 1.6 × 10-19 C.
F=kq2r2=2.3⋅10−22 N.F=\frac{kq^2}{r^2}=2.3\cdot 10^{-22}~N.F=r2kq2=2.3⋅10−22 N.
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