Answer to Question #284418 in Atomic and Nuclear Physics for Ihtesham ullah

Question

A beam of 1MeV electrons strikes a thick target. For a beam

current of 100 microamperes, find the power dissipated in the

target.

Answer 1

Answer:

the power dissipated in the target is 100 W

Explanation:

given data

electrons = 1 MeV =  eV

1 eV = 1.6 ×  J

current = 100 microampere = 100 ×  A

solution

I) when the energy of the beam strikes with 1 MeV so the energy of the electron is

E = e × v

e is a charge of electron and v is voltage

so put here value and we get a voltage

v = 1 ÷ 1.6 × 10^-19

v =  10⁶ volt

II) so the power dissipated in the target

P = voltage × current 

put here value

P =   10⁶ × 100 × 10^-6

P = 100 W

so the power dissipated in the target is 100 W