Question #282992

An electron is traveling at 99.9 percent of the velocity of light. What is its mass?

1
Expert's answer
2022-02-13T12:12:37-0500

m=m01−v2c2=2.04⋅10−29 kg.m=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}=2.04\cdot 10^{-29}~kg.


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