Find the Wronskian of the following functions and determine whether it is linearly dependent or linearly independent on (-∞,∞).
{x2, x+1, x-3} ans, W=8, linearly independent
{3e2x, e2x} ans, W=0, linearly dependent
{x2, x3, x4} ans, W=2x^6, linearly independent
1.
W(x2, x+1, x−3)=det(x2x+1x−32x11200)=2⋅(x+1−(x−3))=2⋅4=8≠0,W(x^2,~x+1,~x-3)=det \begin{pmatrix} x^2 & x+1 & x-3\\ 2x & 1&1\\ 2&0&0 \end{pmatrix}=2\cdot(x+1-(x-3))=2\cdot4=8\not =0,W(x2, x+1, x−3)=det⎝⎛x22x2x+110x−310⎠⎞=2⋅(x+1−(x−3))=2⋅4=8=0, linearly independent.
2.
W(3e2x, e2x)=det(3e2xe2x6e2x2e2x)=6e4x−6e4x=0,W(3e^{2x},~e^{2x})=det \begin{pmatrix} 3e^{2x} & e^{2x} \\ 6e^{2x}& 2e^{2x} \end{pmatrix}=6e^{4x}- 6e^{4x}=0,W(3e2x, e2x)=det(3e2x6e2xe2x2e2x)=6e4x−6e4x=0, linearly dependent.
3.
W(x2, x3, x4)=det(x2x3x42x3x24x326x12x2)=x2(36x4−24x4)−x3(24x3−8x3)+x4(12x2−6x2)=12x6−16x6+6x6=2x6≠0,W(x^2,~x^3,~x^4)=det \begin{pmatrix} x^2& x^3&x^4\\ 2x& 3x^2&4x^3\\ 2&6x&12x^2 \end{pmatrix}=x^2(36x^4-24x^4)-x^3(24x^3-8x^3)+x^4(12x^2-6x^2)=12x^6-16x^6+6x^6=2x^6\not=0,W(x2, x3, x4)=det⎝⎛x22x2x33x26xx44x312x2⎠⎞=x2(36x4−24x4)−x3(24x3−8x3)+x4(12x2−6x2)=12x6−16x6+6x6=2x6=0, linearly independent.
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