Question #281410

Two slits separated by 1.2 mm are placed 1.40 m from a screen. Light of wavelength 480 nm and 640 nm is incident on the slits. What is the separation distance on the screen of intensity maxima of the second order?


1
Expert's answer
2021-12-20T10:30:03-0500

Find the angles for the two wavelengths:


mλ1=dsinθ1,mλ2=dsinθ2. θ1=arcsinmλ1d=0.046°, θ2=arcsinmλ2d=0.061°.m\lambda_1=d\sin\theta_1,\\ m\lambda_2=d\sin\theta_2.\\\space\\ \theta_1=\arcsin\frac{m\lambda_1}{d}=0.046°,\\\space\\ \theta_2=\arcsin\frac{m\lambda_2}{d}=0.061°.

The distance between the maxima:


x=L(tanθ2tanθ1)=0.4 mm.x=L(\tan\theta_2-\tan\theta_1)=0.4\text{ mm}.


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