An electron beam in an X-ray tube is accelerated through 40kV and is incident on a tungsten target. What is the shortest wavelength emitted by the tube?
λmin=hceV=6.62⋅10−34⋅3⋅1081.6⋅10−19⋅40000=0.3⋅10−10 (m)\lambda_{min}=\frac{hc}{eV}=\frac{6.62\cdot10^{-34}\cdot3\cdot10^8}{1.6\cdot10^{-19}\cdot40000}=0.3\cdot10^{-10}\ (m)λmin=eVhc=1.6⋅10−19⋅400006.62⋅10−34⋅3⋅108=0.3⋅10−10 (m)
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