a copper calorimeter of mass 100kg contains 50g of water and 5g of ice at 0 degree celcius.what mass of steam at 100 degree celcius must be passed to the calorimeter to raise the temp to 30 degree celcius.
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Expert's answer
2013-03-19T09:13:47-0400
Qs = Qw + Qc + Qi Qs - lost by steam Qw - gained by water Qc - gained by copper Qi - gained by ice
Qs = L*Ms + (100-30)*Cw*Ms Qw = (30-0)*Cw*Mw Qc = (30-0)*Cc*Mc Qi = R*Mi + (30-0)*Cw*Mi Ms, Mw, Mc, Mi - masses of steam, water, copper and ice Cw=4200 J/(kg*K), Cc=385 J/(kg*K) - heat capacities of water and copper L=2256 kJ/kg - evaporation heat of water R=333 kJ/kg - heat of fusion of water
Q = Qw + Qc + Qi = (30-0)*Cw*Mw + (30-0)*Cc*Mc + R*Mi + (30-0)*Cw*Mi = = 30*4200*0.05+30*385*100+30*4200*0.005+333000*0.005= 1163595 J Q = Qs = L*Ms + (100-30)*Cw*Ms Therefore: Ms = Q/(L+70*Cw) = 1163595 J / ( 2256000+70*4200) J/kg = 1163595/(2256000+70*4200) kg = 0.456 kg = 456 g Answer: 456 g
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