Answer to Question #263898 in Atomic and Nuclear Physics for long

Question

A ball of mass 5 kg is dropped from a height of 1.4 m (from the ground). ) onto a massless spring (a spring with a length balance of 0.5 m). The ball compresses the spring a distance of 0.29 m while at rest. Calculation springs.

Answer 1

h = height fallen by ball

$\frac{1}{2}kx^2 = mgh \\ k = \frac{2mgh}{x^2} \\ h = (1.4-0.5)+0.29 = 1.19 \; m \\ x = 0.29 \; m \\ k = \frac{2 \times 5 \times 9.81 \times 1.19}{(0.29)^2} = 1388 \;N$

Answer: 1388 N