Question #235250

Find the mean square radius of 56Ni nucleus assuming it to be a spherical nucleus with sharp boundary


1
Expert's answer
2021-09-09T10:52:05-0400

Given:

A=56A=56

r0=1.31015mr_0=1.3*10^{-15}\:\rm m


The radius of nucleus

R=r0A1/3R=r_0A^{1/3}

R=1.31015m561/3=5.01015m=5.0fmR=1.3*10^{-15}{\:\rm m}*56^{1/3}=5.0*10^{-15}{\:\rm m}\\=5.0\:\rm fm


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