Question #228928

Two nuclides represented as (70 32X) and (37 17Y) are added to a proton to form anew nuclide. Determine the ratio of a proton-neutron of the new nuclide

Expert's answer

3270X+1737Y+10p=50107Sn,_{32}^{70}X+_{17}^{37}Y+_1^0p=_{50}^{107}Sn,

Z(p)=50,Z(p)=50,

N(n)=10750=57.N(n)=107-50=57.


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