Answer to Question #225459 in Atomic and Nuclear Physics for lakshita

Question

Due to annihilation of electron- positron of same kinetic energy 0.95 MeV, a photon is produced which canalso be produced by an electron of energy E, the possible value of E is ( mass of electron = 9.1 x 10-31 kg, e = 1.6 x 10-19C )

Answer 1

We know that

$E=K+m_0c^2$

$K=E-m_0c^2$

Put value

$$E=(0.95+9.1\times10^{-31}\times(3\times10^8)^2\times931)MeV$$

1amu=931 MeV

$E=(0.95+7.62\times10^{-11})MeV$

$E=0.95MeV$