Question

What is the maximum velocity of a block of mass 2kg attached to a spring of spring constant k=8N/m undergoing simple harmonic motion with an amplitude of 0.1m?

Answer 1

Gives

$m=2kg\\k=8N/m\\A=0.1m\\f=\frac{1}{2\pi}\sqrt{\frac{q}{m}}\\$

Put value

$f=\frac{1}{2\pi}\sqrt{\frac{8}{2}}=\frac{2}{2\pi}=\frac{1}{\pi}$

$w=2\pi f=2\pi\times\frac{1}{\pi}=2$ rad/sec

$v=Aw$

Put value

$v=0.1\times2=0.2m/sec$