Question

What will be the energy of the 5th orbit of hydrogen atom if the energy of the 1st orbit of this atom is 13.6 eV?

Answer 1

Gives

energy of $1^{st}$ orbital H-atom

$E=13.6ev$

n=5

Now

We know that

$$E_n=-\frac{-13.6}{n^2}=\frac{-13.6}{5^2}=-0.544eV$$

$E_5=-0.544eV$