Question

A particular atom emits a photon of wavelength 471 nm when one of its electrons undergoes a transition from one stable energy level to another. If the final energy level has an energy of -6.04 eV, what is the energy of the inital energy level?

Answer 1

Gives

Wavelength ($\lambda)$ =471nm

E_f=-6.04ev

E_i=?

We know that

$E_f-E_i=h\upsilon$

$E_f-E_i=\frac{hc}{\lambda}$

$E_i=E_f-\frac{hc}{\lambda}$

Put value

$$E_i=-6.04eV-\frac{6.625\times10^{-34}\times3\times10^8}{471\times10^{-9}\times1.6\times10^{-19}}$$

$E_i=-6.04-2.64=-8.67eV$