The pitch was clocked at 100.9 mi/hr (45.0 m/s). Determine the impulse required to give a 0.145-kg baseball such a momentum.
By the definition, the momentum is
p=mvp = mvp=mv
p=0.145 kg⋅45 m/s=6.525 kg⋅m/sp = 0.145 \; kg \cdot 45\; m/s =6.525\; kg\cdot m/sp=0.145kg⋅45m/s=6.525kg⋅m/s
Answer: 6.525 [kg m/s]
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