How old is the bone if if it is presently contains 0.3125 g od C-14, but it was estimated to have originally contained 80.000 g of C-14. the half life of Carbon-14 is 5730 years.
n = ?
T = ? years
"n=n_0(\\frac{1}{2})^{\\frac{T}{T_{1\/2}}}"
"0.3125g=80.000g\\times(\\frac{1}{2})^{\\frac{T}{5730years}}"
Solving for T,
T = 45840 years
Answer: 45840 years
Comments
Leave a comment