If 1/f=1/u +1/v
Were u =10.5+-0.1cm and V =85+-0.1cm find minimum error in f
To be given in question
u=u=u= 10.5 cm
Δu\Delta uΔu =-0.1 cm
v=v=v= 85 cm
Δv=\Delta v=Δv= -0.1 cm
To be asked in question
Δf=f(Δuu+Δvv){\Delta f}=f(\frac{\Delta u}{u}+\frac{\Delta v}{v})Δf=f(uΔu+vΔv)
We know that
1f=1u+1u\frac{1}{f}=\frac{1}{u}+\frac{1}{u}f1=u1+u1
Put value then
f=9.3455cmf=9.3455cmf=9.3455cm
Δff=Δuu+Δvv\frac{\Delta f}{f}=\frac{\Delta u}{u}+\frac{\Delta v}{v}fΔf=uΔu+vΔv
Put value
Δf=−9.3455(−0.110.5+−0.185)\Delta f=-9.3455(\frac {-0.1}{10.5}+\frac {-0.1}{85})Δf=−9.3455(10.5−0.1+85−0.1)
Δf=−0.0999cm\Delta f=-0.0999cmΔf=−0.0999cm
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