Answer to Question #171845 in Atomic and Nuclear Physics for Nema

Question

A 50kg cat statue falls from a second floor (10m high) window. With what momentum does it impact the ground with?

Answer 1

The impact velocity

$mgh = \frac{mv^2}{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} = 14 \;m/s$

The momentum:

$p = mv \\ = 50 \times 14 = 700 \;kg \times m/s$