A 50kg cat statue falls from a second floor (10m high) window. With what momentum does it impact the ground with?
The impact velocity
mgh=mv22v=2gh=2×9.8×10=14 m/smgh = \frac{mv^2}{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} = 14 \;m/smgh=2mv2v=2gh=2×9.8×10=14m/s
The momentum:
p=mv=50×14=700 kg×m/sp = mv \\ = 50 \times 14 = 700 \;kg \times m/sp=mv=50×14=700kg×m/s
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