Answer to Question #171845 in Atomic and Nuclear Physics for Nema

Question #171845

A 50kg cat statue falls from a second floor (10m high) window. With what momentum does it impact the ground with?


1
Expert's answer
2021-03-17T08:34:27-0400

The impact velocity

mgh=mv22v=2gh=2×9.8×10=14  m/smgh = \frac{mv^2}{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} = 14 \;m/s

The momentum:

p=mv=50×14=700  kg×m/sp = mv \\ = 50 \times 14 = 700 \;kg \times m/s


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