Question #168422

A single-turn square loop 20.0 cm on a side carries a 1.5 A current.


(a) What’s the loop’s magnetic dipole moment?


(b) What’s the magnitude of the torque the loop would experience if it was in a 2.3T magnetic field with the loop’s dipole moment vector at 60^◦ to the field?


1
Expert's answer
2021-03-09T07:42:15-0500

a)

μ=iA\mu=iA


i(l×w)i(l\times w)


1.5×(20×20)1.5\times(20\times20)


=600A.m2= 600 A.m^{2}


b)

T=μBsin(θ)T=\mu Bsin(\theta)

=600×2.3×sin(60)=600\times2.3\times sin(60)

=1195.12N.m=1195.12N.m



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