After sledging down a hill onto a frozen lake, a boy and a girl are sitting at rest. The combined mass of the kids and the sled is 210 kg. The 70 kg boy jumps north at 6.5 m/s and the 50 kg girl jumps to the south at 8.1 m/s.
How fast and in what direction will the sled be traveling?
The mass of a sledge is "210-70-50 = 90" kg.
We may use the conservation of the linear momentum law. At the initial moment the total momentum is 0 because the system is in rest.
Let the x-axis be directed from the initial point to the north. When kids jump, their linear momentum becomes "m_b v_b - m_gv_g + m_sv_s" and this sum of momenta should also be 0.
Therefore,
"m_sv_s = m_gv_g - m_bv_b, \\;\\; v_s = \\dfrac{m_gv_g - m_bv_b}{m_s}=\\dfrac{50\\cdot8.1-70\\cdot6.5}{90} = -0.56\\,\\mathrm{m\/s}." Therefore, this velocity is directed opposite to the north, namely, to the south.
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