Question #153051
Sodium is a monovalent metal having a density of 0.971 g/cm3 and a molar
mass of 23.0 g/mol. Use this information to calculate (i) the density of charge
carriers and (ii) the Fermi energy of sodium.
1
Expert's answer
2020-12-29T15:32:02-0500

a) ρ = 0.971 g/cm3

M = 23.0 g/mol

V=Mρ=23.00.971=23.68  cm3/mol=23.686.02×1023=3.934×1023  cm3V = \frac{M}{ρ} \\ = \frac{23.0}{0.971} = 23.68 \;cm^3/mol \\ = \frac{23.68}{6.02 \times 10^{23}} = 3.934 \times 10^{-23} \;cm^3

The density of the charge carriers is

ne=1V=18.934×1023=2.54×1022  cm3=2.54×1028  m3n_e = \frac{1}{V} \\ = \frac{1}{8.934 \times 10^{-23}} \\ = 2.54 \times 10^{22} \;cm^{-3} \\ = 2.54 \times 10^{28} \;m^{-3}

b) Fermi energy of sodium is

EF=(3.65×1019)ne23  eV=(3.65×1019)(2.54×1028)23  eV=6.797×0.4645  eV=3.157  eVE_F = (3.65 \times 10^{-19})n_e^{\frac{2}{3}} \;eV \\ = (3.65 \times 10^{-19})(2.54 \times 10^{28})^{\frac{2}{3}} \;eV \\ = 6.797 \times 0.4645 \;eV \\ = 3.157 \;eV


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