tanθ=mgqEtanθ = \frac{mg}{qE}tanθ=qEmg
θ=90–82.6=7.4ºθ = 90 – 82.6 = 7.4ºθ=90–82.6=7.4º
tan(7.4)=7.6×10−3×9.81q×1388.5tan(7.4) = \frac{7.6 \times 10^{-3} \times 9.81}{q \times 1388.5}tan(7.4)=q×1388.57.6×10−3×9.81
q=4.13×10−4 Cq = 4.13 \times 10^{-4} \;Cq=4.13×10−4C
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