The velocity of object at displacement 0.005 m is
v=ω(A2−x2)=2πf(A2−x2)v=\omega \sqrt{(A^2-x^2)}=2\pi f \sqrt{(A^2-x^2)}v=ω(A2−x2)=2πf(A2−x2)
=2π(12)((0.01)2−(0.005)2)=0.653m/s=2\pi (12) \sqrt{((0.01)^2-(0.005)^2)}=0.653 m/s=2π(12)((0.01)2−(0.005)2)=0.653m/s
The maximum velocity is
vmax=ωA=2πfAv_{max}=\omega A=2\pi f Avmax=ωA=2πfA
=2π(12)(0.01)=0.75m/s=2\pi (12)(0.01)=0.75 m/s=2π(12)(0.01)=0.75m/s
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