Answer to Question #141497 in Atomic and Nuclear Physics for GEHAD

Question #141497
The amplitude and frequency of an object executing simple harmonic motion are 0.01 m and 12 Hz respectively. What is the velocity of object at displacement 0.005 m? What is the maximum velocity of the object?
1
Expert's answer
2020-11-02T09:23:51-0500

The velocity of object at displacement 0.005 m is

v=ω(A2x2)=2πf(A2x2)v=\omega \sqrt{(A^2-x^2)}=2\pi f \sqrt{(A^2-x^2)}

=2π(12)((0.01)2(0.005)2)=0.653m/s=2\pi (12) \sqrt{((0.01)^2-(0.005)^2)}=0.653 m/s

The maximum velocity is

vmax=ωA=2πfAv_{max}=\omega A=2\pi f A

=2π(12)(0.01)=0.75m/s=2\pi (12)(0.01)=0.75 m/s


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