Answer to Question #126103 in Atomic and Nuclear Physics for Otika Harmony

Question #126103

What is the wavelength of an electron moving at 5.31×10⁶m/sec?


1
Expert's answer
2020-07-14T09:06:44-0400

Given mass of electron is 9.11×1031kg9.11\times10^{31}kg

h=6.626×1034J.sh=6.626\times10^{34}J.s

de Broglie's Equation is

λ=hmv\lambda=\frac{h}{mv}

λ=6.626×1034J.s9.11×1031kg×5.31×106m/sec\lambda=\frac{6.626\times10^{34}J.s}{9.11\times10^{31} kg\times5.31\times106m/sec}


λ=6.626×1034J.s4.84×1024kg.m/sec\lambda=\frac{6.626\times10^{34}J.s}{4.84\times10^{24}kg.m/sec}

λ=1.37×1010m\lambda=1.37\times10^{10}m

Therefore the wavelength an electron moving is 1.37×1010m1.37\times10^{10}m


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