If the kinetic energy of an electron in the ground state hydrogen atom is 2.2 x 10-18 J, calculate its momentum
The relationship between the momentum and kinetic energy of an electron is
p=(2mK)=(2(9.11∗10−31)(2.2∗10−18))p=\sqrt{(2mK)}=\sqrt{(2(9.11*10^{-31})(2.2*10^{-18 }))}p=(2mK)=(2(9.11∗10−31)(2.2∗10−18))
=2.00∗10−24kg.m/s=2.00*10^{-24} kg.m/s=2.00∗10−24kg.m/s
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