Answer to Question #124772 in Atomic and Nuclear Physics for Albert Eshun

Question

3. A piano string of length 76cm and mass per unit length of 6.91 x 10-3
kg/m is under a
tension of value 40N. What is the frequency of a note sounded by this string

Answer 1

Length of the piano string =76cm = 0.76 m

$\mu$ = 6.91 x 10-3 kg/m

Tension of the value(T)= 40N

$f=[\frac{T}{\mu}]^{\frac{\frac{1}{2}}{2L}}$

$f=[\frac{40}{6.91 * 10^{-3}} ]^{\frac{\frac{1}{2}}{2*0.76}}$

$f = 50.1 Hz$