Answer to Question #122952 in Atomic and Nuclear Physics for Naincy

Question

For a mole of ideal gas at T = 35 ºC, what is the work done for an isothermal expansion from a

volume V0 to 10V0

Answer 1

Isothermal expansion work equals

$A=\nu\cdot R \cdot T \cdot \ln{\frac{V_2}{V_1}}$

Where

$\nu=1 mole$

$R=8.814J/mole \cdot K$

$T=273+35=308K$

$V_1=V_0$

$V_2=10V_0$

Then

$A=1\cdot 8.314 \cdot 308 \cdot \ln{\frac{10V_0}{V_0}}=2561 \cdot\ln{(10)}=5896J$