The orbital quantum number of d electron is l=2l=2l=2
The magnitude of total orbital quantum number for a d-electron in one electron atomic system is
L=l(l+1)h2πL=\sqrt{l(l+1)} \frac{h}{2 \pi}L=l(l+1)2πh
=2(2+1)h2π=6h2π=\sqrt{2(2+1)} \frac{h}{2 \pi}=\sqrt{6} \frac{h}{2 \pi}=2(2+1)2πh=62πh
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!