The orbital quantum number of d electron is l=2l=2l=2
The magnitude of total orbital quantum number for a d-electron in one electron atomic system is
L=l(l+1)h2πL=\sqrt{l(l+1)} \frac{h}{2 \pi}L=l(l+1)2πh
=2(2+1)h2π=6h2π=\sqrt{2(2+1)} \frac{h}{2 \pi}=\sqrt{6} \frac{h}{2 \pi}=2(2+1)2πh=62πh
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I have seen this question in a previous years question paper of a entrance exam and there it shows the answer will be in under root 5. i have not the whole solution of that question. i also got the same answer as you gave me.
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I have seen this question in a previous years question paper of a entrance exam and there it shows the answer will be in under root 5. i have not the whole solution of that question. i also got the same answer as you gave me.