Answer to Question #119709 in Atomic and Nuclear Physics for Higgins

Question

Calculate the total amount of energy released from the fission of 1 kg of U-235.

Answer 1

 

$Q = (235.0439 - 141.9077- 89.9047 - 3\cdot1.0086) = 0.205503\ amu$

$$Q = 191.4\ MeV = 3.15\cdot10^{-11} J$$

$$E=( 3.15\cdot10^{-11})\frac{ 6.023\cdot10^{23}}{0.235}= 8.06\cdot10^{13}J$$